WebDec 12, 2024 · What is the hcf of 825 and 675 and 450 ... HCF of 825,675,450 is 75 Advertisement Advertisement 2sahil 2sahil Hiiiii, The HCF of 825,675,450 is 75. Advertisement Advertisement New questions in Math. faces f + vertices v = edges e + 2is _____ formula .answer atta hai to likho nai to mat likho time barbar mat karo WebWrite each number as a product of its prime factors. 2 2 x 3 x 5 = 60. 3 x 5 2 = 75. The product of all common prime factors is the HCF. The common prime factors in this example are 3 & 5. The lowest power of 3 is 3 and 5 is 5. So, HCF = 3 x 5 = 15. Example 2: Find the HCF of 36, 24 and 12.
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WebFeb 22, 2024 · The required longest rod which can measure the room exactly is the HCF of 825, 675 and 450. First, consider 675 and 450 and apply Euclid’s division lemma, 675 = 450 x 1 + 225 . 450 = 225 x 2 + 0 . Therefore, the HCF (675, 450) = 225 . Now, consider 225 and the third dimension i.e., 825 . By applying Euclid’s division lemma to the above, WebHCF of 825, 675, and 450; HCF of 135 and 225; HCF of 196 and 38220; HCF of 65 and 117; HCF of 4 and 6; HCF of 616 and 32; HCF of 403, 434 and 465; HCF of 20 and 30; HCF of 18 and 24; HCF of 867 and 225; … otterbox 5c cases
The length ,breadth and height of a room are 8m 50cm ,6m …
WebSep 1, 2024 · Answer: 825=3×5×5×11=3×5square×11 675=3×3×3×5×5=33×5square 450=2×3×5×3×5=2×32×5square. From the above, we can say that (3×5square) is … HCF of 825, 675 and 450 can be represented as HCF of (HCF of 825, 675) and 450. HCF(825, 675, 450) can be thus calculated by first finding HCF(825, 675) using long division and thereafter using this result with 450 to perform long division again. 1. Step 1: Divide825 (larger number) by 675 (smaller number). 2. Step … See more Prime factorization of 825, 675 and 450 is (3 × 5 × 5 × 11), (3 × 3 × 3 × 5 × 5) and (2 × 3 × 3 × 5 × 5) respectively. As visible, 825, 675 and 450 have common prime factors. Hence, the … See more WebJan 3, 2024 · Length of room = 8m 25cm = 825 cm Breadth of room = 6m 75m = 675 cm Height of room = 4m 50m = 450 cm ∴ The required longest rod = HCF of 825, 675 and 450 First consider 675 and 450 By applying Euclid’s division lemma 675 = 450 × 1 + 225 450 = 225 × 2 + 0 ∴ HCF of 675 and 450 = 825 Now consider 625 and 825 By applying Euclid’s … otterbox 5s commuter